contestada

First problem - Riley gave the following justification that
n³ − n = n(n + 1)(n − 1) is an identity.
Step 1:
n(n + 1)(n-1)
=
(n² + n)(n-1)
Step 2: = n³ - n² + n²- n
Step 3: = n³ - n
Right side of equation.
Multiply the first two terms.
n³ - n = n(n + 1)(n-1)
Multiplication (distribution).
Combining like terms.
is an identity.
Is this correct (yes or no)? If not, where is the error?

First problem Riley gave the following justification that n n nn 1n 1 is an identity Step 1 nn 1n1 n nn1 Step 2 n n n n Step 3 n n Right side of equation Multip class=