Each random variable (A, B, C, D, E) has two possible outcomes: 0 and 1. The probabilities are given below: P(A= 1) = 0.65 [ 0.2 when A=0 P(B = 1|A) = { 0.7 when A=1 P(C = 11A) – S 0.6 when A=0 1 0.3 when A=1 0.2 when B = 0.C=0 0.7 when B = 1,C = 0 P(D = 1 B, C) = 0.5 when B = 0,C=1 0.8 when B = 1,C = 1 P(E = 1 B, D = 0.7 0.2 0.8 | 0.4 when B=0,D = 0 when B=1,D = 0 when B=0,D=1 when B=1,D=1 1) Express the joint probability of A, B, C, D, E in a factorized form. 2) Compute PE = 1 B = 1, C = 1, D = 1). 3) What is the minimum number of probability numbers we need to store in order to compute the joint probability of A, B, C, D, E? 4) If A, B, C, D, E had three outcomes instead of two (e.g., A, B, C, D, E can be either –1, 0, and 1), what is the minimum number of probability numbers we need to store in order to compute the joint probability of A, B, C, D, E?