[tex]Solve 2x^{2}+5x+2=0 by applying the quadratic formula.x=-\frac{5}{4}+\frac{\sqrt{41}}{4}, x=-\frac{5}{4}-\frac{\sqrt{41}}{4}x=\frac{5}{4}+\frac{\sqrt{41}}{4}, x=\frac{5}{4}-\frac{\sqrt{41}}{4}x=-\frac{1}{2}, x=-2x=\frac{1}{2} x=2[/tex]