h=−21​gt2+v0​t+h0​

The equation above describes the motion of an object thrown upward into the air. In the equation, g is the acceleration due to gravity (9.8 m/s2),t is the time elapsed since the object was thrown upward, v0​ is the initial speed of the object, h0​ is the initial height from which the object was thrown, and h is the height of the object above the ground t seconds after the object was thrown. what is the maximum height from the ground the object will reach to the nearest meters