How many grams of AlCl3 would be produced from 9.24 x 1024 molecules of MgCl2 in the following reaction?

3 MgCl2 + 2 Al(OH)3 ---> 2 AlCl3 + 3 Mg(OH)2

___?__ g AlCl3 = 9.24 x 1024 molecules MgCl2

Round your answer to 3 significant figures