How many grams of Ca(CIO)₂ are formed when 11mL of 0.431M Ca(OH)₂ reacts with excess Cl₂ gas?
2Ca(OH)₂(aq) + 2Cl₂(g) -> Ca(CIO)₂(s) + CaCl₂(aq) + 2H₂O(I)
Molar Mass Ca(CIO)₂ = 142.98 g/mol
A) 2.84 g
B) 3.21 g
C) 4.12 g
D) 5.67 g