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The path of a rocket ship is given by the parametric equations x(t)=3t and y(t)=4t^2+1, where t is the time in seconds after launch. Where is the ship after 10 seconds?
A.) (3,4)
B.) (3,5)
C.) (30,401)
D.) (30,501)

Respuesta :

carlosego
For this case we have the following equations that represent the position of the rocket:
 x (t) = 3t
 y (t) = 4t ^ 2 + 1
 Substituting t = 10 in both equations we have:
 x (10) = 3 (10) = 30
 y (10) = 4 (10) ^ 2 + 1 = 400 + 1 = 401
 Therefore, the position of the rocket is:
 (x, y) = (30, 401)
 Answer:
 the ship after 10 seconds is at:
 C.) (30,401)
Unknownly
The answer is C. (30,401) I already checked.