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PLZZZZZZZZZZ HELP QUICK!!!!!!!!!!!!
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Calculate the diameter of the fifteenth orbit of the hydrogen atom if the diameter of the innermost orbit is 1.06 A. (Hint: Keep three significant figures in your answer.)

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Mindaka
In an atom of hydrogen the orbit radius is given by the formula:
r = n² · α₀

where:
n = number of orbit = 15
α₀ = Bohr radius (innermost radius) = 0.529 Â

Since d = 2 · r, we can write:
d = n² · d₀
   = 15² · 1.06
   =  238.5 Â

Hence, the diameter of the fifteenth orbit of the hydrogen atom is 238.5 Â.

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