Respuesta :

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[tex]y_{min}=-1\ for\ x=(2k+1)\pi\ for\ k\in\mathbb{Z^-}\cup\{0\}\ \vee\ x=\dfrac{3\pi}{2}+2k\pi\ for\ k\in\mathbb{Z^+}\cup\{0\}[/tex]


[tex]y_{max}=1\ for\ x=2k\pi\ for\ k\in\mathbb{Z^-}\cup\{0\}\ \vee\ x=\dfrac{5\pi}{2}+2k\pi\ for\ k\in\mathbb{Z^+}\cup\{0\}[/tex]