contestada

How much grams of Mg(OH)2 is formed if 103g of H2O reacted? (Round answer to the nearest tenths)
Mg2Si+ 4H2O———-> 2Mg(OH)2 + SiH4
(Improvised arrow above
Not an inequality sign)

Respuesta :

transitionstate
Answer:
             117 g of Mg(OH)₂

Solution:
The equation is as follow,

                             Mg₂Si  +  4 H₂O     →     2 Mg(OH)₂  +  SiH₄

According to equation,

            72 g (4 moles) H₂O produces  =  116.64 g (2 mole) Mg(OH)₂
So,
                  103 g of H₂O will produce  =  X g of Mg(OH)₂

Solving for X,
                      X  =  (116.64 g × 103 g) ÷ 72 g

                      X  =  116.86 g ≈ 117 g of Mg(OH)₂