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Four kilograms of carbon monoxide (co) is contained in a rigid tank with a volume of 1 m3. the tank is fitted with a paddle wheel that transfers energy to the co at a constant rate of 14 w for 1 h. during the process, the specific internal energy of the carbon monoxide increases by 10 kj/kg. if no overall changes in kinetic and potential energy occur, determine (a) the specific volume at the final state, in m3/kg. (b) the energy transfer by work, in kj. (c) the energy transfer by heat transfer, in kj, and the direction of the heat transfer.

Respuesta :

jushmk
Part (a): Specific volume
Specific volume, v = V/m, V = Volume of the tank, m = mass of CO in the tank
Therefore,
v = 1/4 = 0.25 m^3/kg

Part (b): Energy transferred in kJ
Work done, W = PΔt, where P = power = 14 W = 14 J/s, t = time = 1 hour = 60*60 = 3600 seconds
Therefore,
W = 14*3600 = 50400 J = 50.4 kJ

Part (c): Energy transferred by heat
ΔU = Q + W
Then,
Heat transferred by heat, Q = ΔU - W
But, ΔU = mΔu = 4 kg*10 kJ/kg = 40 kJ
Therefore,
Q = 40 - 50.4 = -10.4 kJ (negative sign indicates that heat is removed from the CO).
snehashish65

(a) The specific volume at the final state is  0.25 m³/kg.

(b) The energy transfer due to work done is 50.40 kJ.

(c)  The energy transfer by heat transfer is -10.40 kJ.

What is a Specific Volume?

The volume occupied per unit mass of a substance is known as the specific volume of the substance. And mathematically it is equal to the reciprocal of the density of a substance.

Given data:

The mass of carbon monoxide is, m = 4 kg.

The volume of tank is, V = 1 m³.

The energy transfer rate is, P = 14 W.

The time interval is, t = 1 hr = 3600 s.

Increase in internal energy is, U = 10 kJ/kg.

(a) The expression for the specific volume is,

v = V/m

Solving as,

v = 1/4

v = 0.25 m³/kg

Thus, we can conclude that the specific volume at the final state is  0.25 m³/kg.

(b) The expression for the energy transfer due to work done is given as,

W = P × t
Solving as,

W = 14 × 3600

W = 50400 J = 50.40 kJ

Thus, we can conclude that the energy transfer due to work done is 50.40 kJ.

(c) The expression for the energy transfer due to heat is given as,

Q = mU - W

Solving as,

Q = (4 × 10) - 50.40

Q = -10.40 kJ

Thus, we can conclude that the energy transfer by heat transfer is -10.40 kJ.

Learn more about the heat transfer here:

https://brainly.com/question/18338292

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