Respuesta :
The first step for solving this expression is to write all numerators above the least common denominator. For this problem,, our least common denominator will be (x - 3) × (x - 4).
[tex]\frac{2xX(x-4)-4xX(x-3)}{(x-3)X(x-4)} [/tex]
Now we will distribute 2x through the first set of parenthesis.
[tex]\frac{2 x^{2} -8x-4x X(x-3)}{(x-3)X(x-4)} [/tex]
Distribute -4x through the second set of parenthesis.
[tex] \frac{2 x^{2} -8x-4 x^{2} +12x}{(x-3)X(x-4)} [/tex]
Multiply the two parentheses in the denominator of the fraction together.
[tex] \frac{2 x^{2} -8x-4 x^{2} +12x}{ x^{2} -4x-3x+12} [/tex]
Collect the like terms with a variable of x² on the numerator (top) of the fraction.
[tex] \frac{-2 x^{2} -8x+12x}{ x^{2} -4x-3x+12} [/tex]
Collect the terms on the numerator of the fraction with a variable of x.
[tex] \frac{-2 x^{2} +4x}{ x^{2} -4x-3x+12} [/tex]
Lastly,, collect the terms with an x variable on the denominator (bottom) of the fraction to get your final answer.
[tex] \frac{-2 x^{2} +4x}{ x^{2} -7x + 12} [/tex]
Let me know if you have any further questions.
:)
[tex]\frac{2xX(x-4)-4xX(x-3)}{(x-3)X(x-4)} [/tex]
Now we will distribute 2x through the first set of parenthesis.
[tex]\frac{2 x^{2} -8x-4x X(x-3)}{(x-3)X(x-4)} [/tex]
Distribute -4x through the second set of parenthesis.
[tex] \frac{2 x^{2} -8x-4 x^{2} +12x}{(x-3)X(x-4)} [/tex]
Multiply the two parentheses in the denominator of the fraction together.
[tex] \frac{2 x^{2} -8x-4 x^{2} +12x}{ x^{2} -4x-3x+12} [/tex]
Collect the like terms with a variable of x² on the numerator (top) of the fraction.
[tex] \frac{-2 x^{2} -8x+12x}{ x^{2} -4x-3x+12} [/tex]
Collect the terms on the numerator of the fraction with a variable of x.
[tex] \frac{-2 x^{2} +4x}{ x^{2} -4x-3x+12} [/tex]
Lastly,, collect the terms with an x variable on the denominator (bottom) of the fraction to get your final answer.
[tex] \frac{-2 x^{2} +4x}{ x^{2} -7x + 12} [/tex]
Let me know if you have any further questions.
:)
