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What is the equation of the line graphed in the xyxyx, y-plane that passes through the point (-4,-5)(−4,−5)left parenthesis, minus, 4, comma, minus, 5, right parenthesis and is parallel to the line whose equation is 3x-4y=-83x−4y=−83, x, minus, 4, y, equals, minus, 8?

Respuesta :

sqdancefan
The equation of the line through (-4, -5) parallel to 3x-4y=-8 can be written as
  3(x-(-4)) - 4(y-(-5)) = 0
  3x -4y - 8 = 0
  3x - 4y = 8
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