Find the length of the hypotenuse of a right triangle whose legs are 3 and sqrt 2

To begin with, you need to use Pythagorean Theorem (a^2+b^2=c^2)
3 becomes 9
The square root of 2 which is 1.4142135623731
becomes 2
Add those 2 numbers together and you get 11
The square root of 11 is 3.3166247903554
The equation you get is- 3^2+square root of 2^2=3.3166247903554

The length of the hypotenuse is 3.3166247903554

~Revilla03

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ApusApus ApusApus · Answer 2 · 2019-07-03T08:55:16+02:00

Answer:

[tex]\sqrt{11}[/tex] units.

Step-by-step explanation:

We are asked to find the length of the hypotenuse of a right triangle whose legs are 3 and [tex]\sqrt{2}[/tex].

We will use Pythagoras theorem to solve our given problem.

[tex]\text{Leg}^2+\text{Leg}^2=\text{Hypotenuse}^2[/tex]

[tex]3^2+(\sqrt{2})^2=\text{Hypotenuse}^2[/tex]

[tex]9+2=\text{Hypotenuse}^2[/tex]

[tex]11=\text{Hypotenuse}^2[/tex]

Switch the sides:

[tex]\text{Hypotenuse}^2=11[/tex]

Upon taking square root of both sides, we will get:

[tex]\text{Hypotenuse}=\sqrt{11}[/tex]

Therefore, the length of the hypotenuse of the given right triangle is [tex]\sqrt{11}[/tex] units.