Respuesta :
Hi there!
Let's solve this equation step by step!
[tex] |5x + 2| = 8[/tex]
First work out the absolute value, which makes everything between the stripes positive. When we have a negative outcome between the stripes (for instance -8), the stripes make it positive. When we work out the absolute value, we mustn't forget this solution.
[tex]5x + 2 = 8 \: \: or \: \: 5x + 2 = - 8[/tex]
Subtract 2
[tex]5x = 6 \: \: or \: \: 5x = - 10 [/tex]
Divide both sides by 5.
[tex]x = \frac{ 6}{5} = 1 \frac{1}{5}\: \: or \: \: x = -2 [/tex]
~ Hope this helps you!
Let's solve this equation step by step!
[tex] |5x + 2| = 8[/tex]
First work out the absolute value, which makes everything between the stripes positive. When we have a negative outcome between the stripes (for instance -8), the stripes make it positive. When we work out the absolute value, we mustn't forget this solution.
[tex]5x + 2 = 8 \: \: or \: \: 5x + 2 = - 8[/tex]
Subtract 2
[tex]5x = 6 \: \: or \: \: 5x = - 10 [/tex]
Divide both sides by 5.
[tex]x = \frac{ 6}{5} = 1 \frac{1}{5}\: \: or \: \: x = -2 [/tex]
~ Hope this helps you!
Hi there!
| 5x + [tex]2[/tex] | = 8
• Absolute Value :-
The Absolute Value or Modulus | X | of a real number x is the non-negative value of x without regard to its sign.
Which makes the above Eqn's right hand side + ve in both cases.
Then,
Isolatin' the Absolute Value :-
→ For + ve value :
=> 5x + 2 = 8
=> 5x = 8 - 2
=> 5x = 6
=> x = [tex]\dfrac {6}{5}[/tex]
→ For - ve value :
=> 5x + 2 = -8
=> 5x = - 8 - 2
=> 5x = - 10
=> x = [tex]\dfrac {- 10}{5}[/tex] = -2
Hence,
Solution for the Eqn. are :-
=> x = -2 Or => x = [tex]\dfrac {6}{5}[/tex]
~ Hope it helps!
| 5x + [tex]2[/tex] | = 8
• Absolute Value :-
The Absolute Value or Modulus | X | of a real number x is the non-negative value of x without regard to its sign.
Which makes the above Eqn's right hand side + ve in both cases.
Then,
Isolatin' the Absolute Value :-
→ For + ve value :
=> 5x + 2 = 8
=> 5x = 8 - 2
=> 5x = 6
=> x = [tex]\dfrac {6}{5}[/tex]
→ For - ve value :
=> 5x + 2 = -8
=> 5x = - 8 - 2
=> 5x = - 10
=> x = [tex]\dfrac {- 10}{5}[/tex] = -2
Hence,
Solution for the Eqn. are :-
=> x = -2 Or => x = [tex]\dfrac {6}{5}[/tex]
~ Hope it helps!