Respuesta :

gmany
[tex]10x^2y^{-2}[/tex]
Substitute the values of x = -1 and y = -2 to the expression:
[tex]10\cdot(-1)^2\cdoy(-2)^{-2}=10\cdot1\cdot\dfrac{1}{(-2)^2}=10\cdot\dfrac{1}{4}=\dfrac{10}{4}=2.5[/tex]
Used:[tex]a^{-n}=\dfrac{1}{a^n}[/tex]

samuelonum1

Answer:

Substituting the values of x and y will give 38

Step-by-step explanation:

The question seeks to test our understanding of Substitution

Given the expression

10x2y–2 for x = –1 and y = –2.

Substituting for the value of x and y into the expression

We are given x=-1

y=-2

Substituting and equating to zero we have

10(-1)2(-2)-2=0

Opening up The bracket we have

(-10)(-4)-2=0

40-2=0

38=0

The emerging answer is 38

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