Respuesta :
[tex]\bf 2sin(\theta )cos(\theta )+cos(\theta )=0\implies cos(\theta )[2sin(\theta )+1]=0\\\\
-------------------------------\\\\
cos(\theta )=0\implies \measuredangle \theta =cos^{-1}(0)\implies \measuredangle \theta =
\begin{cases}
\frac{\pi }{2}\\\\
\frac{3\pi }{2}
\end{cases}\\\\
-------------------------------[/tex]
[tex]\bf 2sin(\theta )+1=0\implies 2sin(\theta )=-1\implies sin(\theta )=-\cfrac{1}{2} \\\\\\ \measuredangle \theta =sin^{-1}\left( -\cfrac{1}{2} \right)\implies \measuredangle \theta = \begin{cases} \frac{7\pi }{6}\\\\ \frac{11\pi }{6} \end{cases}[/tex]
[tex]\bf 2sin(\theta )+1=0\implies 2sin(\theta )=-1\implies sin(\theta )=-\cfrac{1}{2} \\\\\\ \measuredangle \theta =sin^{-1}\left( -\cfrac{1}{2} \right)\implies \measuredangle \theta = \begin{cases} \frac{7\pi }{6}\\\\ \frac{11\pi }{6} \end{cases}[/tex]
Question:
cos ( 7 pi / 12 ) + cos ( pi / 12 ) =
cos ( 7 pi / 12) - cos ( pi / 12 ) =
Answers:
1. 0.71
2. -1.22
Explanation:
I got it correct in my test :)
