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A cannonball with a mass of 1.0 kilogram is fired horizontally from a 500.-kilogram cannon, initially at rest, on a horizontal, frictionless surface. The cannonball is acted on by an average force of 8.0 × 10 3 newtons for 1.0 × 10 −1 second. What is the magnitude of the change in momentum of the cannonball during firing?

Respuesta :

skyluke89
The impulse J is equal to the magnitude of the force applied to the cannonball times the time it is applied:
[tex]J=F \Delta t[/tex]
But the impulse is also equal to the change in momentum of the cannonball:
[tex]J=\Delta p[/tex]
If we put the two equations together, we find
[tex]F \Delta t= \Delta p[/tex]
And since we know the magnitude of the average force and the time, we can calculate the change in momentum:
[tex]\Delta p= F \Delta t=(8.0 \cdot 10^3 N)(1.0 \cdot 10^{-1} s)=800 kg m/s[/tex]

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