Since it is a right triangle, we can apply the Pythagorean theorem.
The square of the hypotenuse is equal to the sum of the squares of the sides.
We'll call H the hypotenuse and L to the side.
H² = L² + L² = 2L²
H² = 2x11²
[tex]H = \sqrt{2x11^{2}}= 11\sqrt{2}[/tex]
ANSWER = F) = [tex]Diagonal= 11\sqrt{2}[/tex]
[tex]\textbf{Spymore}[/tex]
