(For this, I'll be using the substitution method.)
So firstly, subtract 9 on each side of the first equation. Your equation will look like this: [tex] 2y-9=-x [/tex]
Next, flip the signs around in the first equation. Your equation will look like this: [tex] -2y+9=x [/tex]
Next, substitute x in the second equation for (-2y+9). From there you can solve for y. [tex] 3(-2y+9)-6y=15 [/tex]
Firstly, foil 3(-2y+9). [tex] -6y+27-6y=15 [/tex]
Next, combine like terms: [tex] -12y+27=15 [/tex]
Subtract 27 on each side: [tex] -12y=-12 [/tex]
Lastly, divide -12 on each side, and your answer should be [tex] y=1 [/tex]
To solve for x, just substitute y for 1 in either equation. For this Ill be doing the first equation.
[tex] 2(1)=-x+9 [/tex]
Multiply 2 and 1 [tex] 2=-x+9 [/tex]
Subtract 9 on each side [tex] -7=-x [/tex]
Lastly, flip the signs, and your answer should be [tex] 7=x [/tex]
In short, the answer is (7,1).
