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The complete combustion of ethanol, c2h50h (fw = 46.0 g/mol), proceeds as follows: c2h50h(l) + 3 02(g) ---→ 2 c02(g) + 3 h20(l) llh = -555 kj what is the enthalpy change for combustion of 4.0 moles of c2h50h?

Respuesta :

roberteladrianpbuto8

for 1 mol ethanol ............................ -555 kj

for 4 moles........................................ x => x = -2220kj

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