Respuesta :

common ratio = a4/a3 = a3/a2

8/a3 = a3/18

(a3)^2 = 8 * 18

(a3)^2 = 144

a3 = 12 or a3 = -12

common ratio = 8/12 or common ratio = 8/(-12)

common ratio = 2/3 or common ratio = -2/3

Answer: 12 or -12

The sequences of the given terms are required.

The sequences are [tex]27,18,12,8,\dfrac{16}{3}\ldots[/tex]

and [tex]-27,18,-12,8,-\dfrac{16}{3}\ldots[/tex]

The terms are

[tex]a_2=18\\\Rightarrow ar^{2-1}=18\\\Rightarrow ar=18[/tex]

[tex]a_4=8\\\Rightarrow ar^{4-1}=8\\\Rightarrow ar^3=8[/tex]

Dividing the equations

[tex]\dfrac{a_2}{a_4}=\dfrac{18}{8}\\\Rightarrow \dfrac{ar}{ar^3}=\dfrac{9}{4}\\\Rightarrow \dfrac{1}{r^2}=\dfrac{9}{4}\\\Rightarrow r=\pm\dfrac{2}{3}[/tex]

Common ratio

[tex]r=\dfrac{2}{3}[/tex]

[tex]a\times \dfrac{2}{3}=18\\\Rightarrow a=18\times \dfrac{3}{2}\\\Rightarrow a=27[/tex]

[tex]a_3=ar^2\\ =27(\dfrac{2}{3})^2\\ =12[/tex]

[tex]a_5=27(\dfrac{2}{3})^4\\ =\dfrac{16}{3}[/tex]

[tex]r=-\dfrac{2}{3}[/tex]

[tex]a\times -\dfrac{2}{3}=18\\\Rightarrow a=-18\times \dfrac{3}{2}\\\Rightarrow a=-27[/tex]

[tex]a_3=ar^2\\ =-27(-\dfrac{2}{3})^2\\ =-12[/tex]

[tex]a_5=-27(-\dfrac{2}{3})^4\\ =-\dfrac{16}{3}[/tex]

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