So since its a right triangle, we can use the pythagorean theorem, which is [tex] leg^2+leg^2=hypotenuse^2 [/tex] . Since we know that 2 and 3 are our legs and x is our hypotenuse, we can solve the equation as such:
[tex] 2^2+3^2=x^2\\ 4+9=x^2\\ 13=x^2\\ \sqrt{13}=x [/tex]
Since √13 can't be further simplified, that is your final answer.
