Respuesta :
116c → 115b + 01e
As per equation, one mole of carbon gives one mole of boron which gives 2.87 X 10^11 joules of energy.
Now the mass of one mole of given carbon isotope is 11g / mole
Thus the energy releases from isotope is from 11 grams of carbon
The energy released from 1 gram = 2.87 X 10^11 joules / 11 = 2.61 X 10^10 Joules of energy
Answer:
[tex]2.8977\times 10^{-4} g[/tex] of mass is converted to energy.
Explanation:
Mass of 1 mole of carbon-11 = 11 g
Moles of carbon-11 in 1 gram :
[tex]\frac{1 g}{11 g/mol}=0.0909 mol[/tex]
Energy released when 1 mol of carbon-111 undergoes positron emission: E
[tex]E=2.87\times 10^{11} J[/tex]
Then energy released when 0.0909 moles of carbon-11 undergoes positron emission:
[tex]E'=E\times 0.0909=2.87\times 10^{11} J\times 0.0909 mol=2.608\times 10^{10} J[/tex]
Let the mass converted into energy during the process be m
Using Einstein equation of energy:
[tex]E=mc^2[/tex]
E = energy released
m = mass converted into energy
c = speed of the light
[tex]2.608\times 10^{10} J=m\times (3\times 10^8 m/s)^2[/tex]
m = [tex]2.8977\times 10^{-7} kg=2.8977\times 10^{-4} g[/tex]
[tex]2.8977\times 10^{-4} g[/tex] of mass is converted to energy.
