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Calcium chloride is used to melt ice and snow on roads and sidewalks and to remove water from organic liquids. Calculate the molarity of a solution prepared by diluting 165 ml of 0.688 m calcium chloride to 925.0 ml.

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Answer is: molarity of calcium chloride is 0.123 M.

V₁(CaCl₂) = 165 mL; initial volume of calcium chloride solution.

c₁(CaCl₂) = 0.688 M; initial concentration.

V₂(CaCl₂) = 925.0 mL; final volume.

c₂(CaCl₂) = ?; final concentration.

Use c₁V₁ = c₂V₂.

0.688 M · 165 mL = c₂(CaCl₂) · 925 mL.

c₂(CaCl₂) = (0.688 M · 165 mL) ÷ 925 mL.

c₂(CaCl₂) = 0.123 M.

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