Respuesta :
2*3=6
2*i =2i
3*-5i=-15i
and -5i*i=-5i^2 i^2=-1 so you actually have 5
5-15i+2i+6 simplifies to 11-13i
The standard form of the product of the complex numbers (2−5i)(3+i) is 21 - 13i
Given the product of the complex numbers;
(2−5i)(3+i)
Expanding using distributive law;
[tex]= (2-5i)(3+i) \\= 2(3)+2i-15i-5i^2\\=6-13i-5i^2[/tex]
In complex number, note that i^2 = -1. Substituting this into the result will give;
[tex]=6-13i-15(-1)\\=6-13i+15\\= -13i+21\\= 21-13i[/tex]
Hence the standard form of the product of the complex numbers (2−5i)(3+i) is 21 - 13i
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