[tex]x,\ x+1,\ x+2-\text{the three consecutive integers}\\\\\text{The equation}\\\\x+(x+1)+(x+2)=36\\\\3x+3=36\ \ \ \ |-3\\\\3x=33\ \ \ \ |:3\\\\x=11\\x+1=12\\x+2=13[/tex]
Answer:
n+(n+1)+(n+2)=36
i have done the test :)
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