Respuesta :
Answer:- 3321 kJ of heat is released.
Solution:- The given balanced equation is:
[tex]CH_4+2O_2\rightarrow CO_2+2H_2O, \Delta H=-890\frac{kJ}{mol}[/tex]
From this balanced combustion equation, 890 kJ of heat is released by the combustion of 1 mol of methane.
We could convert given grams of methane to moles and multiply by the delta H value of the reaction to get the total heat released by the combustion of 59.7 grams of methane as:
[tex]59.7gCH_4(\frac{1mol}{16g})(\frac{-890kJ}{1molCH_4})[/tex]
= -3321 kJ
The negative sign indicates the heat is released. So, 3321 kJ of heat is released by the combustion of 59.7 grams of methane.
