The product of the sum of two perfect cubes:
a³ + b³ = (a + b)(a² - ab + b²)
The product of the difference of two perfect cubes:
a³ - b³ = (a - b)(a² + ab + b²)
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Remember to follow FOIL:
(b^2 + 8)(b^2 - 8)
(b^2)(b^2) = b^4
(b^2)(-8) = -8b^2
(8)(b^2) = 8b^2
(8)(-8) = -64
b^4 - 8b^2 + 8b^2 - 64
Combine like terms:
b^4 (-8b^2 + 8b^2) - 64
b^4 - 64
b^4 - 64 is your answer
hope this helps
