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2 NH3 + 2 O2 → N2O + 3 H2O If 80.0 grams of O2 are reacted in the above reaction, how many grams of N2O will be produced (MM O2=32 g/mol; NH3=17.04 g.mol, N2O=44.02 g/mol, H2O=18.02 g/mol)?

29.1 g
67.6 g
55.0 g
165 g

Respuesta :

   2 NH3 + 2 O2 → N2O + 3 H2O

mass of O2 = 80.0g

moles of O2 = 80.0/32 = 2.5 moles O2

moles of N2O = 2.5 moles O2 x   1 mole N2O      = 1.25 moles N2O

                                                       2 moles of O2

mass of N2O produced ;

moles = mass/Molar mass

mass = moles x Molar mass

        = 1.25 x 44.02

        = 55.025 g N2O

       

55.025g of N2O is produced in this reaction.

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