Answer:
In the diagram attached, we will be able to see that the total force [tex]F[/tex] acting on the book is zero, according to the First Newton law, which states that an object is in equilibrium is the total force exerted on it is zero:
[tex]F=F_{T}-W=0[/tex] (1)
Which is the same as:
[tex]F_{T}=W[/tex] (2)
Where [tex]W[/tex] is the weight of the book, which is the product of the mass [tex]m[/tex] of the book and the gravity acceleration [tex]g[/tex]:
[tex]W=mg[/tex] (3)
Being [tex]m=1.0kg[/tex] and [tex]9.8\frac{m}{s^{2}}[/tex], the weight of the book is:
[tex]W=(1.0kg)(9.8\frac{m}{s^{2}})[/tex]
[tex]W=9.8N[/tex] (4)
Then, equation (2) means that the force [tex]W[/tex] due to the weight acting on the book is the same in magnitude but in opposite direction to the force [tex]F_{T}[/tex] the table exerts on the book, which is in accordance with the third Newton law of action and reaction.
