Respuesta :

Answer: 0.6

Work Shown:

P(A or B) = P(A) + P(B) - P(A and B)

P(A or B) = 0.5 + 0.4 - 0.3

P(A or B) = 0.9 - 0.3

P(A or B) = 0.6

Answer:  The required value of [tex]P(A\cup B).[/tex] is 0.6.

Step-by-step explanation:  Given that A and B are two events such that

[tex]P(A)=0.5,~~P(B)=0.4,~~P(A\cap B)=0.3.[/tex]

We are to find the value of [tex]P(A\cup B).[/tex]

From the laws of probability, we have

[tex]P(A\cup B)=P(A)+P(B)-P(A\cap B)=0.5+0.4-0.3=0.9-0.3=0.6.[/tex]

Thus, the required value of [tex]P(A\cup B).[/tex] is 0.6.

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