Answer:
[tex]\tau_a = F a sin \theta[/tex]
Explanation:
The torque of a force is given by:
[tex]\tau = F d sin \theta[/tex]
where
F is the magnitude of the force
d is the distance between the point of application of the force and the centre of rotation of the system
[tex]\theta[/tex] is the angle between the direction of the force and d
In this problem, we have:
[tex]F[/tex], the force
[tex]a[/tex], the distance of application of the force from the centre (0,0)
[tex]\theta[/tex], the angle between the direction of the force and a
Therefore, the torque is
[tex]\tau_a = F a sin \theta[/tex]
