Christines rectangular bedroom has a perimeter of 44 feet. The length of her bedroom is 2 more than the width. What are the dimensions of her room?

Respuesta :

Answer:

Length = 12 feet, Width = 10 feet

Step-by-step explanation:

Let the length of the bedroom be 'x' ft and the width of the bedroom be 'y' ft.

We know that the perimeter of a rectangle is given by,

[tex]P=2(\text {length}+\text {width})[/tex]

[tex]P=2(x+y)[/tex]

It is given that, the length of the bedroom is 2 more than the width, so,

[tex]x=y+2[/tex]

Putting the values in the equation of perimeter we get,

[tex]44=2((y+2)+y)[/tex]

[tex]44=2(2y+2)[/tex]

[tex]\frac{44}{2}=2y+2[/tex]

[tex]22=2y+2[/tex]

[tex]2y=22-2[/tex]

[tex]y=\frac{20}{2}=10[/tex]

Therefore, [tex]x=y+2=10+2=12[/tex]

Hence, the length of the bedroom is 12 feet and the width of the bedroom is 10 feet.

Answer:

L = 12 feet W = 10 feet yuhhhhh