Help me with these math questions..... WITH SCREENIES



[tex]adj(x) = \frac{\sqrt{7}}{3}[/tex]
[tex]opp(y) = \frac{\sqrt{2}}{3}[/tex]
adj² + opp² = hyp²
[tex](\frac{\sqrt{7}}{3})^{2} +(\frac{\sqrt{2}}{3})^{2} = hyp^{2}[/tex]
[tex]\frac{7}{9} +\frac{2}{9} = hyp^{2}[/tex]
1 = hyp²
1 = hyp
sin = [tex]\frac{opp}{hyp} =\frac{\sqrt{2}}{3}[/tex]
cos = [tex]\frac{adj}{hyp} =\frac{\sqrt{7}}{3}[/tex]
tan = [tex]\frac{opp}{adj} =\frac{\sqrt{2}}{sqrt\{7}=\frac{\sqrt{14}}{7}}[/tex]
csc = [tex]\frac{hyp}{opp} =\frac{3}{sqrt\{2}=\frac{3\sqrt{2}}{2}}[/tex]
sec = [tex]\frac{hyp}{adj} =\frac{3}{sqrt\{7}=\frac{3\sqrt{7}}{7}}[/tex]
cot = [tex]\frac{adj}{opp} =\frac{\sqrt{7}}{sqrt\{2}=\frac{\sqrt{14}}{2}}[/tex]
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Answer: 8052
Step-by-step explanation:
[tex]A = Pe^{kt}[/tex]
[tex]5500 = 5000e^{k(3)}[/tex]
[tex]\frac{5500}{5000} = e^{3k}[/tex]
[tex]1.1 = e^{3k}[/tex]
[tex]ln1.1 = lne^{3k}[/tex]
ln1.1 = 3k
[tex]\frac{ln1.1}{3}=k[/tex]
0.03177 = k
[tex]A = Pe^{0.03177t}[/tex]
[tex]A = 5500e^{0.03177(12)}[/tex]
[tex]A = 5500e^{0.3812}[/tex]
[tex]A = 5500(1.4641)}[/tex]
A = 8052.55
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Answer: (2, 9)
Step-by-step explanation:
3x - 8y = -66 → 2(3x - 8y = -66) → 6x - 16y = -132
2x - 7y = -59 → -3(2x - 7y = -59) → -6x + 21y = 177
5y = 45
y = 9
2x - 7y = -59
2x - 7(9) = -59
2x - 63 = -59
2x = 4
x = 2