Help me with these math questions......



Answer: y = 0
Step-by-step explanation:
[tex]\frac{x^{0}}{x^{2}}[/tex]
exponent of denominator > exponent of numerator so, y = 0
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Answer: [tex]y=\frac{x^{2}+8}{3}[/tex]
Step-by-step explanation:
y = [tex]\sqrt{3x-8}[/tex]
To find the inverse, swap the x's and y's and solve for "y":
x = [tex]\sqrt{3y-8}[/tex]
x² = 3y - 8
x² + 8 = 3y
[tex]\frac{x^{2}+8}{3}=y[/tex]
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Answer: -6x - 3h
Step-by-step explanation:
f(x + h) = 7 - 3(x + h)²
= 7 - 3(x² + 2xh + h²)
= 7 - 3x² - 6xh - 3h²
-f(x) = -(7 - 3x²)
= -7 + 3x²
f(x + h) - f(x) = 7 - 3x² - 6xh - 3h² -7 + 3x²
= -6xh - 3h²
= h(-6x - 3h)
[tex]\frac{f(x+h)-f(x)}{h}=\frac{h(-6x-3h)}{h}[/tex]
= -6x - 3h