Answer:
D) [tex](\sqrt[4]{2x -8} )^4 = (-\sqrt[4]{2x + 8} )^4[/tex]
Step-by-step explanation:
The given equation is [tex]\sqrt[4]{2x - 8} + \sqrt[4]{2x + 8 } = 0[/tex]
Before, solve this equation, we have to get rid off the radical sign.
So we move the second term on the other side.
[tex]\sqrt[4]{2x-8} = -\sqrt[4]{2x + 8}[/tex]
Since we have to radical of 4, we need to raise the power to 4 on both sides
[tex](\sqrt[4]{2x - 8)} )^4 = (-\sqrt[4]{2x + 8} )^4\\[/tex]
Thank you.
