Respuesta :
Let [tex]k:y=m_1x+b_1[/tex] and [tex]l:y=m_2x+b_2[/tex]
[tex]l\ \perp\ k\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}[/tex]
We have [tex]y=-45x+3\to m_1=-45[/tex]
Therefore
[tex]m_2=-\dfrac{1}{-45}=\dfrac{1}{45}[/tex]
We have the equation of a line:
[tex]y=\dfrac{1}{45}x+b[/tex]
Put the coordinates of the point (4, 12) to the equation of a line:
[tex]12=\dfrac{1}{45}(4)+b[/tex]
[tex]12=\dfrac{4}{45}+b[/tex] subtract [tex]\dfrac{4}{45}[/tex] from both sides
[tex]11\dfrac{41}{45}=b[/tex]
Answer: [tex]\boxed{y=\dfrac{1}{45}x+11\dfrac{41}{45}}[/tex]