Answer:
option A 9/2
Step-by-step explanation:
limit n-> infinity (9n^3+5n-2)/ 2n^3
to plug in limit value we need to simplify the expression
we divide each term by highest exponent in the denominator
we have n^3 in the denominator
so we divide each term by 2n^3
[tex]\frac{9n^3}{2n^3} + \frac{5n}{2n^3} -\frac{2}{2n^3}[/tex]
Simplify it
[tex]\frac{9}{2} + \frac{5}{2n^2} -\frac{2}{2n^3}[/tex]
now we plug in infinity for n
[tex]\frac{9}{2} + \frac{5}{2∞^2} -\frac{2}{2∞^3}[/tex]
1/ infinity is 0
[tex]\frac{9}{2} +0 -0[/tex]
Answer is 9/2
