[tex]\displaystyle\lim_{n\to\infty}\frac{n^3-2}{n^2}=\lim_{n\to\infty}n-\dfrac2{n^2}[/tex]
As [tex]n\to\infty[/tex], the [tex]\dfrac2{n^2}[/tex] term will converge to 0. The remaining term [tex]n[/tex] will diverge to infinity, so the limit does not exist (D).
