Respuesta :

Answer:

[tex]\frac{41}{4}[/tex]

Step-by-step explanation:

To evaluate h(- 6), substitute x = - 6 into h(x)

h(- 6) = 10 - [tex]\frac{3}{2(-6)}[/tex] = 10 - [tex]\frac{3}{-12}[/tex] = 10 + [tex]\frac{3}{12}[/tex]

h(- 6) = 10 + [tex]\frac{1}{4}[/tex] = 10 [tex]\frac{1}{4}[/tex] = [tex]\frac{41}{4}[/tex]

Answer:

h(x)=10-3/(2x), h(-6)=10+3/12=10.25

h(x)=10-(3/2)x, h(-6)=10+(3/2)×6=19


Step-by-step explanation:

3/2x is ambiguous, because traditional algebra says 3/2x = 3/(2x) but ever since FORTRAN came out in c.1958, programming languages say 3/2x = (3/2)x. WELL IN 1958 COMPUTERS DIDN'T HAVE LOWER CASE, AND XY WAS XY, NOT X*Y, SO IT WAS 3/2*X=(3/2)*X AND NOT 3/(2*X). ALSO FORTRAN IGNORED ALL BLANK SPACES SO X Y WAS ALSO XY NOT X*Y.



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