a ball is dropped into a pond from a height of 42.1m .the splash of sound is heard 3.13seconds after the ball is dropped determine the speed of siund.take g=9.8m/s

Respuesta :

Answer:

  Speed of sound = 210.5 m/s.

Explanation:

Initial height from ground = 42.1 meter.


We have equation of motion , [tex]s= ut+\frac{1}{2} at^2[/tex], s is the displacement, u is the initial velocity, a is the acceleration and t is the time.


In this the velocity of body in vertical direction = 0 m/s, acceleration = 9.8 [tex]m/s^2[/tex], we need to calculate time when s = 42.1 meter.


Substituting


[tex]42.1=0*t+\frac{1}{2} *9.8*t^2\\ \\ t = 2.93 seconds[/tex]


So it will take 2.93 seconds to reach ground.


Extra time taken to hear sound = 3.13 - 2.93 = 0.2 seconds

Distance travelled by sound = 42.1 m

 Speed of sound = Distance / Time = 42.1 / 0.2 = 210.5 m/s.

Speed of sound = 210.5 m/s.