For this case we must factor the equation of the second degree of the form [tex]ax ^ 2 + bx + c = 0[/tex]
To factor, we must find two numbers that when multiplied result in -12, and when summed give as result +1.
Those numbers are +4 and -3.
Taking into account that [tex]+ * - = -[/tex] and that different signs are subtracted and the sign of the major is placed.
[tex](4) * (- 3) = - 12\\+ 4-3 = + 1[/tex]
Thus, the factored expression is:
[tex](x + 4) (x-3) = 0[/tex]
Answer:
[tex](x + 4) (x-3) = 0[/tex]
Answer:(x + 4)(x - 3) = 0
Step-by-step explanation: See here we have to write the given equation in quadratic form.
The equation given here is,
x^2 + x - 12 = 0
i.e. x ^ 2 + 4x - 3x - 12 = 0
i.e. x(x + 4) - 3(x + 4) = 0
Therefore its factored form will be
(x + 4)(x - 3) = 0
Hope it helps!!!
