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I'm not sure what I'm doing wrong in simplifying this square root. I'm factoring out 32 which is 2x2x2x2x2, In this there is 1 set of 5 so I thought the answer would be 1. However, my calculator is telling me its the answer is 2. What did I do wrong?

[tex]\sqrt[5]{32}[/tex]

Respuesta :

Answer:

see explanation

Step-by-step explanation:

note that [tex]2^{5}[/tex] = 2 × 2 × 2 × 2 × 2 = 32, hence

[tex]\sqrt[5]{32}[/tex] = [tex]\sqrt[5]{2^{5} }[/tex] = [tex](2^{5})^{\frac{1}{5} }[/tex] = [tex]2^{1}[/tex] =  2



avapotato

Answer:

2

Step-by-step explanation:

note that 2^{5} = 2 × 2 × 2 × 2 × 2 = 32, hence

\sqrt[5]{32} = \sqrt[5]{2^{5} } = (2^{5})^{\frac{1}{5} } = 2^{1} =  2

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