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The pressure of a 1.0 liter balloon is at 1 atm at 293 K if you were to take the balloon into a freezer that is still at One ATM with a temperature of 263 K what would the new volume of the balloon be

Respuesta :

Here we can say that number of moles as well as pressure will remain same for the balloon

so here we can say by ideal gas equation

[tex]PV = nRT[/tex]

so here for constant pressure and constant number of moles we have

[tex]\frac{V_1}{T_1} = \frac{V_2}{T_2}[/tex]

[tex]\frac{1}{293} = \frac{V}{263}[/tex]

now by rearranging the equation we have

[tex]V = \frac{263}{293}[/tex]

[tex]V = 0.89 Liter[/tex]

so final volume will be 0.89 liter

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