The answer is: -97.37° C
According to the Charles and Gay-Lussac's Law we have that:
[tex]\frac{V}{T}=k[/tex]
Where:
v is the volume of the gas
t is the temperature of the gas
k is the proportionality constant
From the Gay-Lussac's Law we also have the following relation:
[tex]\frac{V1}{T1}=\frac{V2}{T2}[/tex]
Since we need to find the new temperature (T2) we can use the last equation:
[tex]\frac{V1}{T1}=\frac{V2}{T2}\\\\T2=\frac{V2*T1}{V1}=\frac{16.2L*278K}{25.6L}=175.92K[/tex]
We are asked to find the temperature in Celsius degrees, so, we must convert the result (in K) to Celsius degrees:
[tex]Celsius=K-273.15=175.92-273.15=-97.37[/tex]
So, the temperature is -97.37° C
Have a nice day!