Answer:
B. (x + 3, y - 2)
Step-by-step explanation:
Given,
[tex]T: (x, y)\rightarrow (x - 3, y + 2)[/tex],
Let
[tex]T^{-1}: (x, y)\rightarrow (x+a, y+b)[/tex]
[tex]\implies T^{-1}: (x-3, y+2)\rightarrow (x-3+a, y+2+b)[/tex]
Since, [tex]T^{-1}[/tex] is inverse of [tex]T[/tex]
Thus, by the property of inverse function,
x - 3 + a = x ⇒ a = 3
Also, y + 2 + b = y ⇒ b = - 2
By substituting the values,
We get,
[tex]T^{-1}: (x, y)\rightarrow (x+3, y-2)[/tex]
Hence, Option B is correct.
