Respuesta :
[tex]\bf \qquad \qquad \qquad \textit{discriminant of a quadratic} \\\\\\ y=\stackrel{\stackrel{a}{\downarrow }}{a}x^2\stackrel{\stackrel{b}{\downarrow }}{+b}x\stackrel{\stackrel{c}{\downarrow }}{+c} ~~~~~~~~ \stackrel{discriminant}{b^2-4ac}= \begin{cases} 0&\textit{one solution}\\ positive&\textit{two solutions}\\ negative&\textit{no solution}\\ &\textit{two complex roots} \end{cases}[/tex]
bearing in mind that complex (imaginary) roots are never by their lonesome, their sibling sister is always with them.
Answer: Two complex roots (choice A)
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Explanation:
Let D be the discriminant of a quadratic.
The general rule is
- If D is a positive number (ie larger than 0), then you have two different real roots.
- If D is equal to 0, then you have exactly one real root
- If D is negative, then you'll have two imaginary or complex roots.
In this case, the discriminant is D = -8. That satisfies D < 0 which is the third case mentioned above.