Respuesta :
Answer:
The equation of the path
y = 5x + 3
Step-by-step explanation:
It is given that, a particle moves from coordinates (0, 3) to coordinates (1, 8).
To find the slope
Slope = (y₂ - y₁)/(x₂ - x₁)
= (8 - 5)/(1 - 0) = 5
To find the equation of line
Let (x₁, y₁) = (0, 3)
(y - y₁)/(x - x₁) = 5
(y - 3)/(x - 0) = 5
(y - 3)/x = 5
y - 3 = 5x
y = 5x + 3
ANSWER
[tex]y = 5x + 3[/tex]
EXPLANATION
If particle moves from coordinates (0, 3) to coordinates (1, 8) and it traces a linear path, then its equation can be obtained using the formula;
[tex]y=mx + c[/tex]
We calculate the slope of this line using
[tex]m = \frac{y_2-y_1}{x_2-x_1} [/tex]
[tex]m = \frac{8 - 3}{1 - 0} = 5[/tex]
The point (0,3) is the y-intercept of the line, hence c=3.
The equation of the line is therefore;
[tex]y = 5x + 3[/tex]
[tex]y = 5x + 3[/tex]
EXPLANATION
If particle moves from coordinates (0, 3) to coordinates (1, 8) and it traces a linear path, then its equation can be obtained using the formula;
[tex]y=mx + c[/tex]
We calculate the slope of this line using
[tex]m = \frac{y_2-y_1}{x_2-x_1} [/tex]
[tex]m = \frac{8 - 3}{1 - 0} = 5[/tex]
The point (0,3) is the y-intercept of the line, hence c=3.
The equation of the line is therefore;
[tex]y = 5x + 3[/tex]