Respuesta :

luisejr77

Answer: Option D.

Step-by-step explanation:

The equation of the line in point-slope form is:

[tex]y-y_1=m(x-x_1)[/tex]

Where m is the slope of the line and ([tex]x_1,y_1[/tex]) is a point of the line.

Given the points (-1,1) and (1,-5), you can find the slope with the formula [tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]. Then:

[tex]m=\frac{-5-1}{1-(-1)}=\frac{-6}{2}=-3[/tex]

Substitute the slope and the point (-1,1) into  [tex]y-y_1=m(x-x_1)[/tex]:

 [tex]y-1=-3(x-(-1))[/tex]

 [tex]y-1=-3(x-+1)[/tex]

kudzordzifrancis

ANSWER

D.

[tex]y - 1 = - 3(x + 1)[/tex]

EXPLANATION

The point-slope form equation is calculated using the formula:

[tex]y-y_1=m(x-x_1)[/tex]

Where m is the slope, which is calculated using the formula:

[tex]m = \frac{y_2-y_1}{x_2-x_1} [/tex]

Let

[tex](x_1,y_1)=(-1,1)[/tex]

and

[tex](x_2,y_2)=(1, - 5)[/tex]

We substitute the points to obtain;

[tex]m = \frac{ - 5 - 1}{1 - - 1} [/tex]

[tex]m = \frac{ - 6}{2} = - 3[/tex]

We also substitute the point and slope to obtain;

[tex]y - 1 = - 3(x - - 1)[/tex]

Simplify the expression in the parenthesis to get;

[tex]y - 1 = - 3(x + 1)[/tex]

The correct choice is D.